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0.5x^2+11x-8500=0
a = 0.5; b = 11; c = -8500;
Δ = b2-4ac
Δ = 112-4·0.5·(-8500)
Δ = 17121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{17121}}{2*0.5}=\frac{-11-\sqrt{17121}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{17121}}{2*0.5}=\frac{-11+\sqrt{17121}}{1} $
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